Question

find the smallest number which leave remainder 4 in each case when divided by 22 and 26?​

Answer 1

Prime factorizations first.

12 = 2 x 2 x 3

15 = 3 x 5

18 = 2 x 3 x 3

27 = 3 x 3 x 3

LCM = 2 x 2 x 3 x 3 x 3 x 5 = 540

Since all of the remainders are 4 less than the divisors, the number will be 540 - 4 = 536