Question

find the smallest number which leave remember 8 and 12 when divided by 28 and 32 respectively

Answer 1

Answer:

232

Step-by-step explanation:

LCM of 28 and 32 = 224

224 + 8 = 232

Hence, 232 is the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively.