find the smallest number which leaves 1 as remainder when divided by 24 and 60
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Answered by
1
3 maybe the answer
becaz when we divide 3 by 1 it remainds 1
3 is the factor of 24 and 60
becaz when we divide 3 by 1 it remainds 1
3 is the factor of 24 and 60
Answered by
0
your answer is 121
121 is the smallest number which want
the smallest common number multiply by both 24 and 60 is 120.
if we divide 24 with 121 then the remainder is 1. also in 60 and 121.
121 is the smallest number which want
the smallest common number multiply by both 24 and 60 is 120.
if we divide 24 with 121 then the remainder is 1. also in 60 and 121.
luieazkenzpb63ax:
how did u solve it
yaaa
ok write somehow how to solve
3/2=1 and 3×8=24and 3×20=60
i modify my answer
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