Find the smallest number which leaves 4 as remainder when divided by 44,55,66
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Find the smallest number which leaves 4 as remainder when divided by 44,55,66.
Answer
To find:- The smallest number which leaves 4 as remainder when divided by 44,55,66.
The required number = LCM of the number+remainder
Firstly,we find their LCM.
By prime factorization:
44 = 2 × 2 × 11
55 = 5 × 11
66 = 2 × 3 × 11
LCM = 2² • 3 • 5 • 11 = 660
Therefore, the LCM is 660
Based on Q ,it leaves remainder which is 4
Therefore, (660+4)=664
★The required number is 664.
More to know
LCM stands for Lowest Common Multiple
A multiple is a number that your get when you multiply any number by a whole number (<0)
it's been in use since the 1870s
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