find the smallest number which leaves 5 reminder when divided by 37 and 87
Answers
Answered by
4
Step-by-step explanation:
37-5=32
87-5=82
then,find lcm of 32,82
2×2×2×4×41
=128
ans= 128
Answered by
1
Answer:
the smallest number be x
37-5=32
87-5=82
the LCM of 32,82 is 1312
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