Question

Find the smallest number which leaves a remaindee of 5 when divided by 24 32 and 42

Answer 1

Answer:

Now N, when divided by 24, 32 & 42 leaves remainder 5. In other words, (N-5) will be completely divisible by 24, 32 and 42 and the least as well. So, (N-5) has to be the LCM of 24, 32 & 42.

Step-by-step explanation:

24/32=1

8/24=3

3/42=14

HOPE THIS HELPS

Answer 2

Step-by-step explanation:

24=3×2×2×2

32=2×2×2×2×2

42=7×3×2

L•C•M=3×7×2×2×2×2×2

=21×32

=672

So required number is

672+5=677