Math, asked by akshitashekarshah, 2 months ago

Find the smallest number which leaves a remainder 7 when divided by 20,50,75

Answers

Answered by purvajaiswal520

4

Answer:

Find the LCM of 20, 42 and 76.

20 = 2x2x5

42 = 2x3x7

76 = 2x2x19

The LCM is 2x2x3x5x7x19 = 7980.

Next add 7 to 7980 to get 7987 as the answer.

Check: 7987 divided by 20 = 399 as quotient and a remainder of 7. Correct.

7987 divided by 42 = 190 quotient and a remainder of 7. Correct.

7987 divided by 76 = 105 quotient and a remainder of 7. Correct.

7987 is the answer.

Step-by-step explanation:

Answered by dsingh15028

1

Answer:

Find the LCM of 20, 42 and 76.

20 = 2x2x5

42 = 2x3x7

76 = 2x2x19

The LCM is 2x2x3x5x7x19 = 7980.

Next add 7 to 7980 to get 7987 as the answer.

Check: 7987 divided by 20 = 399 as quotient and a remainder of 7. Correct.

7987 divided by 42 = 190 quotient and a remainder of 7. Correct.

7987 divided by 76 = 105 quotient and a remainder of 7. Correct.

7987 is the answer.

Step-by-step explanation:

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