Question

find the smallest number which leaves a remainder 8 and 12 when divided by 28 and 32 respectively

Answer 1

Plz mark my answer as brainlist

Answer 2

LET x be the no

SO when 28/x r=8

=>x is divisible by 28-8=20

SImilarly 32 /x r=12

So x is divisible by 32-12=20

BUt we know that lcm of 20,20 is 20

hence 20 is the ans

marK me brainliest