Question

Find the smallest number which leaves a remainder of 5 when divided by 24,32 and 42.
Find the smallest​

Answer 1

Answer:

677

Step-by-step explanation:

Let the number be ‘N'.

Now N, when divided by 24, 32 & 42 leaves remainder 5.

In other words, (N-5) will be complely divisible by 24, 32 and 42 and the least as well.

So, (N-5) has to be the LCM of 24, 32 & 42.

LCM (24, 32, 42) = 672 = (N-5)

So, N = 677 (Answer)

Note: In general, if we have multiple Divisors giving the same Remainder, then the number is given as:

[N = LCM of Divisors + Remainder]

Hope this helps u.

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Answer 2

Step-by-step explanation:

When smaller number we should do LCM but if larger number we should do HCF.

I hope it helps you