Question

find the smallest number which leaves a remainder of 5 when divided by 24, 32 and 42
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Answer 1

Answer:

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Answer 2

Answer:

Now N, when divided by 24, 32 & 42 leaves remainder 5. In other words, (N-5) will be complely divisible by 24, 32 and 42 and the least as well. So, (N-5) has to be the LCM of 24, 32 & 42.

Step-by-step explanation:

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