Question

find the smallest number which leaves a remainder of 5 when divided by 24 32 and 42.
tell correct answer​

Answer 1

Answer:

(N-5)

explainatio:

Let the number be 'N'. Now N, when divided by 24, 32 & 42 leaves remainder 5. In other words, (N-5) will be complely divisible by 24, 32 and 42 and the least as well. So, (N-5) has to be the LCM of 24, 32 & 42

Answer 2

Answer:

ok ok take rest get well soon