Question

Find the smallest number which leaves a remainder of 8 when divided by 15,20 and 54

Answer 1

Answer:

Brainly.in

What is your question?

Secondary School Math 5 points

Q.- The least number which when divided by 12 15 20 and 54 leaves in each case a remainder of 8 is:

a-582.

b-548.

c-854.

d-584

Ask for details Follow Report by Shubhjitspyadav 15.06.2018

Answers

kishanswaroopya

kishanswaroopya Ace

LCM of 12, 15, 20, 54

12 = 2 x 2 x 3

15 = 3 x 5

20 = 2 x 2 x 5

54 = 2 x 3 x 3 x 3

LCM = 27 x 4 x 5 = 27 x 20

= 540

ADD 8

= 540 + 8 = 548

Therefore, the answer is 548 that is 'B'

Answer 2

Answer:

548

Step-by-step explanation:

lcm of 15,20,54 =540

add 8 to 540=548

hence ans =548