Question

find the smallest number which leaves remainder 7in each case 35,45,70

Answer 1

Here is your answer dear⬇️⬇️

First we will find the LCM of 35, 45, 70


35 = 5 × 7

45 = 5 × 3 × 3

70 = 2 × 5 × 7

LCM = 630



$\therefore{}$ Least number = 630 + 7 = 637


▶️Least number is 637