find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32
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204 is the smallest numbers which when divided by 28 and 32 u will get remainder 8 and 12.
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Answer:
Step-by-step explanation:
Given that the smallest no. When divided by 28 & 32 leaves remainder 8 & 12.
Therefore, 28–8=20 & 32–12=20 are divisible by the required number will be 20 less than the LCM of 28 and 32.
28= 2² x 7
32 = 2^5
So, LCM = 2^5 * 7 = 224
Therefore, 224–20=204…
Hence, the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 is 204…
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