Question

find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32

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Answer 1

Answer:

First subtract the remainder from given number

28-8=20 , 32-12 =20

Now lcm of 20

that is 20

So 20 is the smallest number which leaves the remainder 8 and 12 when divided by 28 and 32.

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Answer 2

Answer:

given that the dmallest number when divided by 28 and 32 leaves remainder 8 and 12 respectivly 28 - 8 = 20 and 32-12=20 are divisible by the required numbers

therfore the required number will be 20 less than the LCM of 28 and 32 is =224