find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively
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= 28-8 = 20 = 2 . 2 . 5 = 2^2 . 5
= 32-12 = 20 = 2 . 2 . 5 = 2^2 . 5
smallest no. should be equal to their HCF
HCF = 2 . 2 . 5 = 20.
= 32-12 = 20 = 2 . 2 . 5 = 2^2 . 5
smallest no. should be equal to their HCF
HCF = 2 . 2 . 5 = 20.
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