Question

Find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32

respectively. class 10​

Answer 1

Answer:

Given that the smallest number when divided by 28 and 32 leaves remainder 8 and 12 respectively. 28 - 8 = 20 and 32 - 12 = 20 are divisible by the required numbers. Therefore the required number will be 20 less than the LCM of 28 and 32. = 224.