Question

find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively​

Answer 1

Find LCM ( 28,32) = 224.
Then add 8 and 12 which is 20 and subtract it from LCM.
i.e., 224 - 20 = 204.
So, 204 is the smallest number which divided by 28 and 32 and leaves remainder 8 and 12 respectively.

Answer 2

Bonjour!!

Hey mate here is your answer!!

When we subtract 8 from 28 and 12 from 32 we get 20

So, LCM is 20

Therefore, 20 is a no. which divides 28 and 32 leaving reaminder 8 and 12 respectively.

Hope this helps...!!!