Question

Find the smallest number which leaves remainder 8 and12 when divided by 28 and 32 respectively​

Answer 1

Answer: The smallest number which leaves remainder of 8 and 12 when divided by 28 and 32 is 20.

Step-by-step explanation:

Firstly subtract 8 from 28. So 28 - 8 = 20.

Then subtract 12 from 32. So 32 - 12 = 20.

Now find HCF of 20 and 20.

HCF of (20,20) = 20.

Therefore, 20 is the required number.

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Answer 2

Step-by-step explanation:

28-8=20

32-12=20

HCFof 20 and20=20

therefore20is the required number