Question

Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32
respectively,
​

Answer 1

okkk friend hmmmmmm to uuuu

Answer 2

Answer:

Given that the smallest number when divided by 28 and 32 leaves remainders 8 and 12 respectively. 28-8= 20 and 32-12= 20 are divisible by the required numbers. Therefore the required number will be less than 20 the LCM of 28 and 32= 224.