Question

Find the smallest number which leaves the remainder 5 when divided by 15,20 and 35

Answer 1

ANSWER:

• Required number = 425

GIVEN:

• Number = 15 ; 20 and 35
• Required remainder = 5

TO FIND:

• Required number.

SOLUTION:

For finding the smallest number we have to find the LCM of the given number.

=> 15 = 3*5

=> 20 = 2*2*5

=> 35 = 5*7

LCM = (2*2*5*7*3)

LCM = 420

Required remainder = 5

So we have to get 5 remainder in each case we have to add 5 in the LCM.

Required number = 420+5

=425

NOTE:

• In this type of person we have to first find the LCM of the the given number.
• Then add the reminder to get the required number.