Question

Find the smallest number which leaves the remainder 5 when divided by 15, 20 and 35.​

Answer 1

Answer:

Firstly, we will find the LCM of 15, 20 and 35

15 = 3 x 5

20= 2 x 5 x 2

35 = 7 x 5

@ 92

LCM = 420

Now, we will add 5 to 420

420 + 5 = 425

.. The number is 425