Find the smallest number which leaves the remainder 5 when divided by 15,20 and 35
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Answer:
Procedure
We have to find LCM of these numbers and add 5 to it, to obtain our number
LCM
The LCM of 15, 20 and 35 is 420
Adding 5 to the Result
We, now, need to add 5 to the LCM of 15, 20 and 35
LCM of 15, 20 and 25 = 420
Number = 420 + 5
Number = 425
So, 425 is the smallest number, which when divided by 15, 20 or 35, leaves a remainder of 5
Checking
425 ÷ 15
Quotient - 28
Remainder - 5
425 ÷ 20
Quotient - 21
Remainder - 5
425 ÷ 35
Quotient - 12
Remainder - 5
So, the answer is correct
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