Math, asked by shubhangikadam0806, 4 months ago

Find the smallest number which leaves the semainder
5 when divided
by 15,20,35

Answers

Answered by SajanJeevika

3

425 is the correct answer as L.C.M. of 15,20 ad 35 is 420. So required no. =420+5=425.

Answered by shambhavibiswas26655

1

Answer:

425

Explanation :

LCM of 15, 20, 35 = 420

420 + the reminder

= 420 + 5

= 425

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