find the smallest number which mean reduced by 2 becomes divisible by 24 48 and 64
Answers
Answered by
0
Answer:
Let the smallest number be x.
so in question they are tell that
(x-2)/24∈ positive integers ;
(x-2)/48∈ positive integers ;
(x-2)/64∈ positive integers ;
LCM of 24,48,64=64
so the smallest value of x which satisfies (x-2)/64 will be the answer
the smallest multiple of 64=1
so, (x-2)/64=1
x-2=64
x=64+2
x=66
Answered by
0
Answer:
12
Step-by-step explanation:
24/2=12
48/2=24
64/2=32
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