Question

Find the smallest number which must be added to 43216 to make it divisible by : 3​

Answer 1

Answer:

it hvcggdhdhxhbfncnncbfnbffbjfnchchvhvh jncnfncncn

Answer 2

Step-by-step explanation:

Step 1) Divide 43216 by 3

43216÷3

quotient = 14405

remainder = 1

Step 2) Subtract remainder i.e. 1 from 43216

43216-1 =43215

Step 3)Add 3 to 43215 to get it divisible by 3

43215+3=43218

Step 4) Subtract 43218-43216

43218-43216=2

2 is the smallest number which can be added to get 43216 to get divisible by 3.

Hope it helps ;)