Question

Find the smallest number which, on being added 23 to it, is exactly
divisible by 32, 36, 48 and 96.

Answer 1

Answer:

36 is the anweryoyoyoyoyoy

Answer 2

Answer:

Step-by-step explanation:

First le's find LCM of 32,36,48 and 96

The prime factors of 32,36,48 and 96 are:

$32= 2^5\\\\36= 4 \times 9 =2^2 \times 3^2\\\\48= 16 \times 3 =2^4 \times 3\\\\96=32 \times 3=2^5 \times 3\\\\Thus \ LCM ( 32,36,48,96)\\\\=2^5 \times 3^2\\\\32 \times 9 =288\\\\Now \ we \ need \ a \ number\ which \ on\ addition \ of\ 23 \ is\\divisible \ by \ 32,36,48\ and \ 96\\\\\bf Such \ number =288-23 =265$