Math, asked by sharmasheela534, 1 month ago

find the smallest number which on being added 23 to it is exactly divisible by 32,36,48 ,96
please ans fast

Answers

Answered by oishiyadav

0

Answer:

265 is the required smallest number which, on being added 23 to it, is exactly divisible by 32, 36, 48 and 96

Answered by afranjalaljv

0

Answer:

265 is exactly divisible by 32,36,48,96

When it is added to 23

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