Math, asked by prabhatkumarya82, 10 months ago

Find the smallest number which on being added 5 to exactly divisible 9,21,25,45

Answers

Answered by ab192k

0

Answer:

1570

Step-by-step explanation:

Find gcd

GCD will be the minimum number divisible by all the numbers

you will be adding 5 to the number so subtract gcd with 5

GCD -5 = 63*25-5

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