Question

Find the smallest number which on being added 5 to exactly divisible 9,21,25,45​

Answer 1

Answer:

1570

Step-by-step explanation:

To find the smallest number firstly let's find the LCM of 9,21,25,45

3|9,21,25,45

3|3,7,25,15

5|1,7,25,5

5|1,7,5,1

7|1,7,1,1

|1,1,1,1

LCM = 3*3*5*5*7 = 1575

Hence, the smallest number is 1575-5= 1570