find the smallest number which on being added 5 to it is exactly divisible by 9,21,25 and 45
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Answer:
First of all we will find the LCM of the numbers 9, 21, 25 and 45. Now the LCM will be 1575 then we will subtract 5 from 1575 , now our answer will be 1579
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I hope you understand
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