Question

Find the smallest number which, on being decreased by 2, is completely divisible by 18, 36,32 and 27.​

Answer 1

Answer:

the number when decreased by 2 will be the LCM of 18 36 32 and 27

18 =2×3×3

36=2×2×3×3

32=2×2×2×2×2

27=3×3×3

LCM (18,36,32,27) = 2×2×2×2×2×3×3×3 = 864

the required number is 864 + 2 = 866

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