Math, asked by meherbhat209, 6 months ago

Find the smallest number which on being decreased by 3, is completely divisible by 24, 36 and 40.

Answers

Answered by saikrisha2006

3

Answer:

L.C.M. of 18, 36, 32 and 27

= 2 × 2 × 3 × 3 × 3 × 8 = 864

∴ required number = 864 + 3 = 867

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