Find the smallest number which on dividing by 6 8 12 leaves the remainder 4 6 10 respectively
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15
6×4=24
8×6=48
12×10=120
Answered by
3
Let x be a smallest number which on dividing by 6,8 and 12 leaves the remainder 4,6 and 10 respectively.
To find:
Smallest number x
Solution:
LCM(6,8,12)=
By using Euclid's division algorithm
Hence, 142 is the smallest number which on dividing by 6,8 and 12 leaves remainder 4,6 and 10 respectively.
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