Question

Find the smallest number which on subtracting 43 to it is exactly divisible by 25, 30 and 65.​

Answer 1

Step-by-step explanation:

Hcf of 25, 30,65

$25 = 5 \times 5 \\ 30 = 5 \times 2 \times 3 \\ 65 = 5 \times13$

Hcf is 5

So

$43 - x = 5 \\ x = 38$

Then smallest number is 38 which subtract from 43 to give a number which is exactly divisible by 30,25,65