Find the smallest number which we get by multiplying it with 100 to get perfect
cube.
3
Write a Pythagorean triplet whose one number is 12.
step by step
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Part - I
To find:
✠ The smallest number which we get by multiplying it with 100 to get perfect cube.
Solution:
Let's understand the concept first!
- A perfect cube has three as powers of the prime factors.
- In this question, the power of 2 is 2s and that of 5 is also 2s ( 2² and 5² )
- We need to multiply 2 and 5 further to obtain the smallest number to make perfect cube of 100 by multiplying it with 100. So, it will be 2 × 5 = 10
Let's find out...✧
By prime factorization method,
2 | 100
2 | 50
5 | 25
5 | 5
| 1
➛ 2 × 2 × 5 × 5
➛ 2 × 2 × 5 × 5
➛ 2 × 5 = 10
∴ 100 should be multiplied by 2 × 5 = 10 to get perfect cube.
Part - II
To find:
✠ A Pythagorean triplet whose one number is 12.
Solution:
We know that in the Pythagoras triplet in general form is 2m, m² - 1 and m² + 1
We know that one number in a Pythagorean triplet is 12.
So, Let us take
➤ 2m = 12
➤ m = 12/2
➤ m = 6
Now, find a Pythagorean triplet
➛ m² - 1
➛ 6² - 1
➛ 36 - 1
➛ 35
➛ m² + 1
➛ 6² + 1
➛ 36 + 1
➛ 37
∴ The required Pythagorean triplet is 12, 35 and 37.
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