Question

Find the smallest number which were divisible by 18,27,36 leave remainder 5 in each case

Answer 1

Answer:

$18 + 27 + 36 \\ 5each \: case \\ \\ \frac{18 + 27 + 36}{5} \\ \\ \frac{81}{5} \\ \\ = 16.2each$

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Step-by-step explanation:

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