Question

find the smallest number which whebmn divided by 48,60and 84,leaves a remainder of 5 in each case​

Answer 1

Answer:

565

Step-by-step explanation:

Let’s see straight through it…. All three numbers will only divide a number when all of them are factors of it. So it’s obvious we need to find the LCM.

16 = 2^4

28 = 2^2 X 7

40 = 2^3 X 5

LCM = 2^4 X 7 X 5 (Taking the highest power of the nos.)

LCM = 560

So 560 Is the smallest number which the above three nos divide . But what is requested is that the smallest number which leaves the remainder 5.

So if we increase 5 from 560 , everytime these three nos will leave a remainder as 5. (Isn’t that obvious) :)

Hence the no. will be 560+ 5 = 565