Question

find the smallest number which when added to 5 is divisible by 12,14 and 18​

Answer 1

Answer:

Step-by-step explanation:

Find the lcm (12,14,18)

12 = 2^2 * 3

14 = 2*7

18 = 2 * 3^2

l.c.m = 2^2 * 3^2 * 7 = 252

So,252 is the smallest number which is divisible by each of 12,14 and 18.

252-5 = 247

Hence 247 is the smallest number which when added by 5 is divisible by 12,14,18.

Hope it helps

Answer 2

Take LCM of 12, 15 and 18.

Factors are

12=2*2*3,

15=3*5,

18=2*3*3.

Their LCM=2*2*3*3*5

=180.

Because smallest 5 digits number is 10000.

Let us divide it by 180

then for a quotient 55 remainder is 100

if we add 80 to it then it will be completely divided by 180 with a quotient 56.

Therefore 180*56=10080

So smallest 5 digits number divisible by 12, 15, and 18

is 10080