Math, asked by sunitasingh36836, 5 hours ago

Find the smallest number which when decreased by 1 is completely divisible by 15, 12 and 40

Answers

Answered by nityabhattxd

3

Answer:

121 should be the answer because 15 × 8 = 120, 12 × 10 = 120 and 40 × 3 = 120

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