Question

find the smallest number which when decreased by 1 is exactly divisible by number 21 45 63 81​

Answer 1

Answer:

Step-by-step explanation:

To find the least number, we need to find the LCM of 21, 45, 63, 81​

21= 3×7

45= 3×3×5

63= 3×3×7

81= 3×3×3×3

LCM= 5670

5670+1= 5671

5671 is the smallest number which when decreased by 1 is exactly divisible by number 21, 45, 63, 81.

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