Find the smallest number which when decreased by 11 is exactly divisible by both 420 and 168.
Answers
Answer:
23 is the smallest number which when decreased by 11 is exactly divisible by both 420 and 168.
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Answer:
Here is your answer buddy,
Step-by-step explanation:
Question,
Find the smallest number which when decreased by 11 is exactly divisible by both 420 and 168.
Answer,
Points that we should know,
How to find LCM,
etc...
LCM of 420 and 168 by listing multiples,
420 multiples =
- 420, 840, 1260, 1680, 2100,2520, 2940, 3360, 3780,4200etc..
168 multiples =
- 168, 336, 504, 672, 840, 1008, 1176, 1344, 1512, 1680, 1848 etc...
Therfore,
LCM of 420 and 168 by prime factorisation,
2 | 420 , 168
---------------
2 | 210 , 84
---------------
3 | 105 , 42
---------------
7 | 35 , 14
---------------
5 | 5 , 2
---------------
2 | 1 , 2
---------------
| 1 , 1
LCM OF 420 AND 168
= 2 × 2 × 2 × 3 × 7 × 5
= 840
So, we found that LCM OF 420 and 168 is 840
Solution,
A number decreased by 11 will be the smallest divisible number of 420 and 168
Let the number be X,
X - 11 is th smallest divisible number of 420 and 168
X - 11 = LCM OF 420 AND 168
X - 11 = 840
X = 840 + 11
X = 851
SO, THE REQUIRED NUMBER IS 851
(TO FIND LCM USE PRIME FACTORIZATION METHOD FOR TIME SAVING AND IT IS THE EASY WAY )