Find the smallest number which when decreased by 3 is completely divisible by 18,27,32 and 36
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Answered by
2
Answer:
867
Step-by-step explanation:
L.C.M. of 18, 36, 32 and 27
= 2 × 2 × 3 × 3 × 3 × 8 = 864
∴ required number = 864 + 3 = 867
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