Question

find the smallest number which when decreased by 4, is completely divisible by 18 36 32 27​

Answer 1

Answer:

the smallest number is 3

Answer 2

Step-by-step explanation:

First of all we find the LCM of 18, 36, 32 and 27.

18=2×3×318=2×3×3

36=2×2×3×336=2×2×3×3

32=2×2×2×2×232=2×2×2×2×2

27=3×3×327=3×3×3

LCM=864

864 is the smallest integer which is divisible by 18, 36, 32 and 27.

Hence the smallest integer which needs to be decreased by 3 is 864 + 3 = 867.

867 when decreased by 3 will be divisible by 18, 36, 32 and 27.

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