Find the smallest number which when devided by 17,23 and 32 leaves remainder 5 in each case.
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Firstly we will find LCM of 17,23 and 32.
(find yourself )
The answer will be 2*2*2*2*2*17*23
= 12512
As 12512 is divisible by all three numbers so, we will plus 12512 with 5 - 12517
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