Math, asked by MohammedRehanSiddiq, 8 months ago

Find the smallest number which when devided by 38, 52 and
65 leaves a remainder of 5 in each case

Answers

Answered by divyanshyada7

3

Answer:

4940 is the smallest no. divisible by 38,52 and 65. So after adding 5 it will leave remainder 5 in each case.

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