Math, asked by kajalkadam956, 1 year ago

find the smallest number which, when devided by 52, 62 and 72, leaves 2 as remainder.​

Answers

Answered by niswarravirao00
0

Answer:

Aug 20, 2017 - So, the smallest number is 785, which when divided by 39, 52 and 65 leaves a remainder of 5 in each case. So, when 785 is divided by 39, 52 and 65, the remainder is 5 in each case.

Step-by-step explanation:

Answered by vinodsuriya685335
0

Step-by-step explanation:

Its answer is 10

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