Question

find the smallest number which when divide by 10 and 15 leaves no remainder​

Answer 1

Answer:

30

Step-by-step explanation:

Smallest number which when divided by 10 and 15 leaves no remainder = LCM of 10 and 15

10 = 2×5

15 = 3×5

Hence, LCM = 2×3×5 = 30

Therefore, the number is 30.

Answer 2

FInd the smallest number which when divide by 10 and 15 leaves no remainder​

Explaination:

• Smallest number dividible by any two numbers = HCF of these numbers .
• $15=5*3$, means , HCF = $30$.
• Hence,$30$ is the smallest number which is divisible by both $10$ and $15$.

Calculation:

$10=2*5\\15=3*5$

LCM$=2*3*5$

LCM = $30$

Prime factorization

• Prime factorization is a way of expressing a number as a product of its prime factors.
• A prime factor is a number that has exactly two factors, 1 and the number itself.
• The number $6$ is expressed as $2*3$ since $3$ and $2$ are prime numbers.
• Therefore,the prime factorization of $30$ is $2*3*5$.