Find the smallest number which when divide by 44 and 55,leaves a remainder of 8
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Answer:
228
Step-by-step explanation:
BY TAKING THE LCM OF 44 AND 55 WE GET
= 11×4×5
=220
SO THE NUMBER WHICH CAN BE TOTALLY DIVIDED BY 44 AND 55 IS 220
BY ADDING 8 TO 220
= 220+8
= 228
WHICH WHEN DIVIDED BY 44 AND 55 LEAVES THE REMAINDER 8
THANK YOU
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