find the smallest number which when divided 24,30,55 leaves remainder 18
Answers
Answered by
1
Answer:
1085
Step-by-step explanation:
The prime factor of 24 is (2^3)*3
The prime factor of 30 is 2*3*5
The prime factor of 54 is 2*(3^3)
I calculated the prime factor of the LCM to be (2^3)*(3^3)*5, which equals to 1080, then add five.
The smallest number which when divided by 24, 30, and 54 leaves five as a remainder in each case is 1085.
Hope you understand
Answered by
0
Answer:
Step-by-step explanation:
24,30,55 -18=243037
243037
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